33 votes 33 votes A network has a data transmission bandwidth of $20 \times 10^{6}$ bits per second. It uses CSMA/CD in the MAC layer. The maximum signal propagation time from one node to another node is $40$ microseconds. The minimum size of a frame in the network is __________ bytes. Computer Networks gatecse-2016-set2 computer-networks csma-cd numerical-answers normal + – Akash Kanase asked Feb 12, 2016 • edited Jan 6, 2018 by pavan singh Akash Kanase 9.4k views answer comment Share Follow See 1 comment See all 1 1 comment reply Kuljeet Shan commented May 24, 2019 reply Follow Share https://gateoverflow.in/3834/gate2005-it-71?show=312877#a312877 Check answer here for all similar questions. 0 votes 0 votes Please log in or register to add a comment.
–1 votes –1 votes In Csma/Cd ,Transmission Time(TT)=2*Propagation Delay ... Then Let x be Frame size .... X/(20*10^6)=2*40*10^-6 => X= 1600 bits = 200 bytes Puja Mishra answered Jan 31, 2017 Puja Mishra comment Share Follow See all 2 Comments See all 2 2 Comments reply Kaushik.P.E commented Feb 1, 2017 reply Follow Share Transmission Time should be >= 2 * propagation time. It need not be equal. As the question ask for minimum packet size, we assume it to be equal. 3 votes 3 votes Puja Mishra commented Feb 1, 2017 i edited by Puja Mishra Jan 23, 2018 reply Follow Share yeah i hav assumed it ... like the answer above ... 0 votes 0 votes Please log in or register to add a comment.
