ISRO CSE 2014 | Question: 3

Question

What is the output of the following C program? 

#include<stdio.h>
#define SQR(x) (x*x)  

int main()
{
    int a;
    int b=4;
    a=SQR(b+2);
    printf("%d\n",a); 
    return 0;
}

• A. 14
• B. 36
• C. 18
• D. 20

Answer 1

The macro function SQR(x)(x*x) calculate the square of the given number 'x'. (Eg: 10²)

Step 1: int a, b=4; Here the variable a, b are declared as an integer type and the variable b is initialized to 4.

Step 2: a = SQR(b+2); becomes,

=> a = b+2 * b+2; Here SQR(x) is replaced by macro to x*x .

=> a = 4+2 * 4+2;

=> a = 4 + 8 + 2;

=>a=14

Answer 2

Ans will be 14

#include <stdio.h>
#define SQR(x) (x*x)
 
int main(void) {
	int a;
	int b=4;
	a=SQR(b+2); // here it will compute (b+2*b+2)=4+2*4+2=4+8+2=14
	printf("%d",a);
	return 0;
}

Comments

thank u

Answer 3

It will print 14.

Because due to macro expression will get converted into

b + 2 * b + 2 === > 4 + 2 * 4 + 2 ==> 14

Answer 4

preprocessor expands, a = SQR(b+2); as

a= x + 2 * x + 2

a= 4 + 8 + 2

a = 14

option A would be the answer

Answer 5

a =SQR(b+2)=b+2*b+2=4+2*4+2=4+8+2=14

Comments

thank u!

Answer 6

Consider the given program
#include<stdio.h>
int main()
{
int a;
int b=4;
a=SQR(b+2);//a=b+2*b+2
printf("%d\n",a);
return 0;
}

Here SQR(x) is replaced by macro to x*x

a=SQR (b+2)

  =b+2 * b+2

   = 4+2 * 4+2

   =4+8+2

So the program assign a=4+8+2=14 to variable a.14 will be printed .