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Give reasons why one might conjecture that the following language is not deterministic. $L =$ { $a^nb^mc^k : n = m$ or $m = k...
336
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For the language $L =$ {$a^nb^{2n} : n ≥ 0$}, show that $L^*$ is a deterministic context-free language.
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Is the language $L =$ {$a^nb^n : n ≥ 1$} $∪$ {$a$} deterministic?
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Is the language $L =$ {$a^nb^n : n ≥ 1$} $∪$ {$b$} deterministic?
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Show that $L =$ {$a^nb^m : m ≥ n + 2$} is deterministic.
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Show that $L =$ {$a^nb^{2n} : n ≥ 0$} is a deterministic context-free language.
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Give a construction by which an arbitrary context-free grammar can be used in the proof of Theorem 7.1.Theorem 7.1: For any context-free language L, there exists an npda ...
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Give full details of the proof of Theorem 7.2 .Theorem 7.2 : If L = L (M) for some npda M, then L is a context-free language.
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Find a context-free grammar that generates the language accepted by the npda $M =$ ({$q_0,q_1$}, {$a,b$}, {$A, z$}$,δ, q_0, z,$ {$q_1$}), with transitions ...
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find an npda for the language $L = ${ $ww^R : w ∈$ {a, b}$^+ $}
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Show that the npda in Example 7.8 accepts L (aa*b).Find the grammar that generates Example 7.8 and prove that this grammar generates the language L (aa*b).show that the v...
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Find an npda with two states that accepts $L =$ {$a^nb^{2n} : n ≥1$}.
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Find an npda with two states for the language $L =$ {$a^nb^{n+1} : n ≥ 0$}.
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Show that “For every npda $M$, there exists an npda $\widehat M$ with at most three states, such that $L (M) = L (\widehat M )$.Show how the number of states of $\wideh...
288
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Construct an npda corresponding to the grammar $S\rightarrow aABB|aAA,$ $A\rightarrow aBB|a,$ $B\rightarrow bBB|A.$
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Construct an npda that accepts the language generated by the grammar $S → aSSS|ab$.
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Construct an npda that accepts the language generated by the grammar $S\rightarrow aSbb|aab$.
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Prove that the pda in Example 7.6 accepts the language $L =$ {$a^{n+1}b^{2n} : n ≥ 0$ }.
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Show that the pda constructed in Example 7.6 accepts the string $aaabbbb$ that is in the languagegenerated by the given grammar.Example 7.6: Construct a pda that accepts...
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We can define a restricted npda as one that can increase the length of the stack by at most onesymbol in each move, changing Definition 7.1 so that $\...