pointer arithmatic

Question

#include <stdio.h>

int main(void) {
    
static    char s[25]="TheCocaine Man";
    int i=0;
    char ch;
    ch=s[++i];
    
    printf("%c",ch);
    ch=s[i++];
    printf("%c \n",ch);
   ch=i++[s];
   printf("%c\n",ch);
   ch=++i[s];
   
   printf("%c ",ch);
    return 0;

}

how last ch print D?is  ++i[s] incremet index or value?

Comments

@arjun sir  ,,++i[s] increment index or value?

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Array operator has higher precedence. So, increments the value.

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thanks sir..got it..

@arjun , @aayushranjan01

 can we increment index in same pattern using pre-increment?

Answer 1

1) S[i] = *(S+i) = *(i+S) =i[S]

2) ++S[i] = ++*(S+i) = ++*(i+S) = ++i[S]

In second case --> ++i[S] is expanded to ++*(i+S) by the preprocessor. * and ++ both are unary operators and priority are same for both. So they will go for Right to Left associativity. So first *(i+S) will be computed which equals "C" and then is incremented to D

Comments

1 and 2 are correct. But 2 is the work of preprocessor?

http://en.wikipedia.org/wiki/C_preprocessor

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@akash @arjun sir ..  apology for wrong info. Is it the work of compiler ? I'm not sure.

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Yes. It is. Because [] is a language feature. And this translation is equivalent, but not always done. If compiler does this translation, then indexed addressing can no longer be used.

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can any one explain me what i++[s] line mean?