Packet Fragmentation on Routers [GateBook]

Question

Answer 1

If No Packets is dropped Then The Condition should be like this :

 Let T be the input rate  , so our formula is  :  Input rate - output rate = Buffer Size     .....(i)

 Since 1 packet remains in the buffer for 12 ms time period.  And Avg length of the packet is 200 B.

 In 12 ms data  buffered is  200*8 bits   .

  So output rate in 1 Sec is (200*8)/12 * 10^-3  bits   ...(ii)

Now,   T - output rate  = 256 *8 * 10³ bits/sec ...(iii) we get this from (i)  [ as buffer size = 256 KBps = 256 * 8 * 10³ bits/sec ]

now put the output rate value of (ii) in (iii)  and we get 

 T = 272.66 bits/Sec

Comments

neither i got the question nor solution. What do they mean by average arrival rate?

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It want to say express your answer in bits per second .

What do they mean by average arrival rate?

It means, the average number of arrivals per unit of time.

For example, if a buffer can store h = 3 packets per hour, on average, then 1/h = 1/3 hr = 20 min is the average arrival time for one packet.

The reciprocal, 1/h, of the average rate of arrival is the average time required to buffer one packet.

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understood!

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Sir how output rate is determined ?

The packet is coming inside the buffer and staying there for 12ms and after that it will be transmitted by the router,So how output rate is determined?

Please explain @Bikram Sir