C program

Question

What is the error in the following code . Please do correct them

#include <stdio.h>
int main () { 
char *x[5] = {"raju","ramu","tinu","ben","ali"};
printf("%s\n",(x[2][0]) );
    return 0;
}

Answer 1

#include <stdio.h>
int main () {
char *x[5] = {"raju","ramu","tinu","ben","ali"};
printf("%s\n",(x[2]) );
    return 0;
}

[0] is not required.

O/P should be "TINU". %s format specifier prints charachters until null character is encountered. And enclosing charachters in double quotes automatically makes it null terminating.

Comments

Thanks. @Kaushik.P.E

Doubts

• What is the change in printf if i need to access 2nd letter of 3rd word ?
• Can u pls show how this will be stored in memory (if possible ) because not able to understand why not [0] is not required
• How do print the address of word 2

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If %s format specifier is used, the variable to be printed must be a pointer to a charchter array.

 x[2][0] derefers to the first charchter in the third string. And hence using %s format specifier will not work. If you use %c then the first charchter in the third string will be printed for x[2][0]. And use ampersand and unsigned int format specifier to print address of the second word.