1,988 views

1 Answer

1 votes
1 votes
There are Two Nodes

n1 and n2

probability of n1=0.8(p1)

probability of n2=x(p2)

probability of success full transmission of packet from node 1=0.8*(1-x)

probability of success full transmission of packet from node 2=x*(1-0.8)

given troughput to attain for S1 =1mbps

therefore  for node 2

10/1=x*0.2

x=0.5(probabilty of node 2)

throughput for node 1=0.8*(1-x) -> 0.8*0.5 ->.4

.4*10mbps= 4mbps (for node 1)

total throughput of network 4mbps + 1mbps =5 mbps

 

 

please correct me ,where i am wrong...

Related questions

5 votes
5 votes
1 answer
1
MiNiPanda asked Jan 8, 2018
4,548 views
Groups of user stations(N) share a 56Kbps pure aloha channel. Each station outputs a 1000 bits frame on an average of once every 100sec(stations are buffered). What is th...
0 votes
0 votes
0 answers
2
Phantom5 asked Aug 21, 2018
242 views
Quoted:What data rate is needed to transmit an uncompressed 4" x 6" photograph every second with a resolution of 1200 dots per inch and 24 bits per dot (pixel)?1. 691,200...
1 votes
1 votes
1 answer
4
PieChuckerr asked Feb 2, 2017
798 views
In Operating System we have process scheduling and page fault numerical which are hot favorite and comes very often. What are the hot favorite questions in CO and Archite...