9 9 votes How many different $\text{BCD}$ numbers can be stored in $12$ switches ? (Assume two position or on-off switches).$2^{12}$$2^{12}-1$$10^{12}$$10^3$ Digital Logic isro2014 digital-logic number-representation + – jenny101 8.9k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Vivek sharma commented Jul 17, 2015 reply Follow flag is the answer d ? 0 0 replyShare Akhil Nadh PC commented Jun 25, 2016 reply Follow flag Edit : Title : ISRO 2014 SET A Question 27 0 0 replyShare Please log in or register to add a comment.
Best answer 21 21 votes 1 Switch is equivalent to 1 bit Cz Switch store either on or off value like a bit can be 0 or 1. So total 12 bits are there(cz there 12 switches) Make 3 group of 12 bit . Means each group contain 4 bit. (_ _ _ _) (_ _ _ _) (_ _ _ _) G1. G2. G3 Here in any group max 10 numbers can be stored Cz BCD numbers we have to store. So 10*10*10 different BCD numbers can be stored in this 12 Switches. So Ans is option D) 10^3 Rajesh Pradhan answered Jun 24, 2016 • selected Jun 24, 2016 by jenny101 Rajesh Pradhan comment Share Follow 0 reply Please log in or register to add a comment.
8 8 votes With 4 bit we can represent 10 BCD no. 12 switches means 12 bit space. Total 10*10*10 BCD no. Digvijay Pandey answered Jul 17, 2015 Digvijay Pandey comment Share Follow See all 3 Comments 3 3 Comments reply aditya dhanraj commented Jun 18, 2016 reply Follow flag can you explain your solution. it is not clear to me. how it is 10*10*10. 1 1 replyShare Sourabh Kumar commented Jun 20, 2016 reply Follow flag how please explain? 0 0 replyShare vandana commented Jul 11, 2016 reply Follow flag Decimal Num Binary Num BCD Num 0 0000 0000 1 0001 0001 2 0010 0010 3 0011 0011 4 0100 0100 5 0101 0101 6 0110 0110 7 0111 0111 8 1000 1000 9 1001 1001 10 1010 0001 0000 11 1011 0001 0001 12 1100 0001 0010 13 1101 0001 0011 14 1110 0001 0100 15 1111 0001 0101 12 Switches --> 12 bits are divided into 3 groups as each group contains 4 bits, hence we can store maximum 10 BCD numbers in that 4 bits i.e., from 0-9 so probability of each group is 10 and total 3 groups=10*10*10 Hope this will clear your doubt. 2 2 replyShare Please log in or register to add a comment.
4 4 votes BCD numbers = 4 bit. Switch = 1 bit. (either on or off) So, in 12 switches, we can store $\frac{12}{4}=3$ BCD numbers. A BCD number ranges from 0 - 9. So 10 total values. So, $10^3$ Option D JashanArora answered Dec 8, 2019 JashanArora comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote Answer : 10^3 Have a look at it : https://gateoverflow.in/13388/solve shekhar chauhan answered Jun 14, 2016 shekhar chauhan comment Share Follow See all 2 Comments 2 2 Comments reply asu commented Jun 14, 2016 reply Follow flag 12 switch means 12 bit means ?? 0 0 replyShare Rajesh Pradhan commented Jun 24, 2016 reply Follow flag 1 Switch is equivalent to 1 bit Cz Switch store either on or off value like a bit can be 0 or 1. 0 0 replyShare Please log in or register to add a comment.