2 votes 2 votes y = | x^2- 2 | how to draw graph of such equation sumit goyal 1 asked Aug 16, 2017 sumit goyal 1 377 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply joshi_nitish commented Aug 16, 2017 i edited by joshi_nitish Aug 16, 2017 reply Follow Share firstly put inside mod part =0(it will give points where mod changes its behaivior) x2 - 2 = 0 x= $\sqrt{2}$ , $-\sqrt{2}$ using inequality principle you will find that, y >=0 , x belongs (-$\infty$ , $-\sqrt{2}$ ] $\cup$ [$\sqrt{2}$ , $\infty$) < 0 , x belongs ($\sqrt{2}$ , $-\sqrt{2}$) divide regions like this, y = { x2 - 2, x belongs (-$\infty$ , $-\sqrt{2}$ ] $\cup$ [$\sqrt{2}$ , $\infty$) // upward parabola = 2 - x2 , x belongs ($-\sqrt{2}$, $\sqrt{2}$) // downward parabola } corresponding graph, 1 votes 1 votes sumit goyal 1 commented Aug 16, 2017 reply Follow Share here what the dotted line represents ?? 0 votes 0 votes joshi_nitish commented Aug 16, 2017 reply Follow Share you have taken mirror image of dotted part 1 votes 1 votes sumit goyal 1 commented Aug 16, 2017 reply Follow Share thnks bro got it :) 0 votes 0 votes sumit goyal 1 commented Aug 16, 2017 reply Follow Share in last line though it dont have effect 2 - x2 , x belongs to ( --- √2 , √2) // downward parabola correct me if iam wrong 0 votes 0 votes joshi_nitish commented Aug 16, 2017 reply Follow Share yes you are correct, edited. 1 votes 1 votes Please log in or register to add a comment.