0 votes 0 votes What is mean here by word size=4 Byte ? Please solve the below question CO and Architecture co-and-architecture + – Harikesh Kumar asked Jan 30, 2018 Harikesh Kumar 408 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply gauravkc commented Jan 30, 2018 reply Follow Share Word addressable. Which means 224 words is the physical address memory not bytes. But please someone solve this question. The solution given is not clear. 0 votes 0 votes hs_yadav commented Jan 31, 2018 reply Follow Share ..let node down all the parameter first... physical address is 24 bits... line/block size=128byte/4=32word=25 .word tag memory size is....211 bytes or 29 word ... physical address partision... offset tag Set 5 x 19-x then tag memory size is...=tag*lines x*219-x+4 bits/ 4byte = 29word x*219-x+4-3-2=18-x word=.29word x*218-x = 29 ...(problem how to decide the value of x..) vale of x=13..then answer would not matched.... case 2:- if we assume that tag memory = equal to 2tag bits .... that is also not matching with given scenario... :- Note:- in my openion this question having lack of information 1 votes 1 votes Ashwin Kulkarni commented Jan 31, 2018 reply Follow Share Yes after converting everything to word addressible i also got stuck where @hs is! Because that equation can’t be solved! :( lack of information or questions arrangement is wrong i guess 0 votes 0 votes _jerry commented Jan 31, 2018 reply Follow Share Thank you @ hs_yadav and @ Ashwin Kulkarni 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes how to calculate cache m/m size? and tag m/m size Anshul Shankar answered Jan 31, 2018 Anshul Shankar comment Share Follow See all 0 reply Please log in or register to add a comment.