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Probability - Gravner-51.a

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Probability for No 1 Appears = $\frac{5}{9}$

Probability(No 1 Appears) for 10 Dice = $(\frac{5}{9})^{10}$

Probability(at least one 1 Appears) = 1 - $(\frac{5}{9})^{10}$
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