Hashing + Counting , Source : ME OTS

Question

Anyone please give a solution to solve such question as it is difficult in one go.

Comments

@HeadShot

He solved it in lengthy way.

so we need to have {2,13,24} before 12,62 and 82

also we need to have 77 placed before 82.

now {2,13,24} can be arranged in 3! ways.

for representing further steps i will take the help of the below representation (this is one of the 3! possible representation of {2,13,24})

__ 2 __ 13 __ 24 __ 12 __ 62 __ 82 __

we know that 77 should come before 82 hence the possible places are 

 __ 2 __ 13 __ 24 __ 12 __ 62 __ 82             i.e.. 6 places

the following is one of the 6 representations

__ 2 __ 13 __ 77 __ 24 __ 12 __ 62 __ 82 __        

now we have 8 possible places to place 91.

hence answer is 3!*6*8 = 288

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Where is 12 ??

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@pradeepchaudhary it is explanation of this question ....

https://gateoverflow.in/188101/hashing-test-series