2 votes 2 votes “n/m” means that n is a factor of m, then the relation T is (a) reflexive and symmetric (b) transitive and symmetric (c) reflexive, transitive and symmetric (d) reflexive, transitive and not symmetric Ans: option (d) But how ? Set Theory & Algebra set-theory&algebra relations + – Prasanna asked Nov 27, 2015 Prasanna 2.3k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes For relation to be symmetric if (m,n) belong to R then (n,m) also belongs to R ie m is factor of n and n is factor of m this is possible only when m=n this relation is antisymmetric for eg(2,4) belongs to R but (4,2) does not belong to r so ans is d Pooja Palod answered Nov 27, 2015 Pooja Palod comment Share Follow See all 2 Comments See all 2 2 Comments reply Prasanna commented Nov 27, 2015 reply Follow Share Then how this is reflexive ? 0 votes 0 votes Prashant. commented Nov 27, 2015 reply Follow Share every no. divide itself. like n/n. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Suppose u have elemens like below ways :: R={(1,2)(2,1)} 2%1==0 but 1%2!=0 that's why A relation with "\" will never be symmetric but it is obvious that it will be by the definition of the reflexive and transitive u will get a relation "\" will be both as previous. Paras Nath answered Sep 19, 2016 Paras Nath comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes n is the factor of m. n is also the factor of itself similarly for m then it is reflexive. n is the factor of m but it is not necessary that m is the factor of n, it can only possible when n=m, so it is not symmetric. and if m/l then it implies n/l then it is transitive so the answer is d it is reflexive, transitive but not symmetric namvar answered Aug 3, 2018 namvar comment Share Follow See all 0 reply Please log in or register to add a comment.