0 votes 0 votes Show that $F = \{a^{i}b^{j}\mid i = kj$ $\text{for some positive integer $k$\}}$ is not context free$.$ Theory of Computation michael-sipser theory-of-computation context-free-language + – admin asked May 4, 2019 • edited May 4, 2019 by Lakshman Bhaiya admin 265 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes but, the given expression is context-free where we can prove it by using PDA in which we push every kth a onto the stack and will pop a for every b. thus, proving it to be context-free. Sathuri Bharath answered May 5, 2019 Sathuri Bharath comment Share Follow See all 0 reply Please log in or register to add a comment.
