1 votes 1 votes $\underset{x \to 0}{\lim} \sin \bigg( \dfrac{1}{x} \bigg)$ equals $-1$ $0$ $1$ Does not exist Calculus isi2015-dcg calculus limits + – gatecse asked Sep 18, 2019 • recategorized Nov 14, 2019 by Lakshman Bhaiya gatecse 451 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply `JEET commented Nov 14, 2019 reply Follow Share B? 0 votes 0 votes Priyansh Singh commented Jun 10, 2020 reply Follow Share D ? 1 votes 1 votes neeraj_bhatt commented Sep 7, 2020 reply Follow Share It think it’s a misprint, it should be lim x→0 x.sin(1 / x), because a same question was there in ISI 2015 0 votes 0 votes `JEET commented Feb 27, 2022 reply Follow Share Yes. 0 votes 0 votes Please log in or register to add a comment.