0 votes 0 votes Is the sequence $\{a_{n}\}$ a solution of the recurrence relation $a_{n} = 8a_{n−1} − 16a_{n−2}$ if $a_{n} = 0$ $a{n} = 1$ $a_{n} = 2^{n}$ $a_{n} = 4^{n}$ $a_{n} = n4^{n}$ $a_{n} = 2 \cdot 4^{n} + 3n4^{n}$ $a_{n} = (−4)^{n}$ $a_{n} = n^{2}4^{n}$ Set Theory & Algebra kenneth-rosen discrete-mathematics set-theory&algebra descriptive + – admin asked Apr 19, 2020 admin 180 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.