0 votes 0 votes Verbal Aptitude general-aptitude virtual-gate-test-series + – abhinowKatore asked Jan 17, 2023 • retagged Jan 17, 2023 by makhdoom ghaya abhinowKatore 491 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes $logP=100Q-100R$ $logQ=100R-100P$ $logR=100P-100Q$ Assuming base of log as $2$, $P=2^{100Q-100R}$ $Q=2^{100R-100P}$ $R=2^{100P-100Q}$ So, $PQR=2^{100Q-100R+100R-100P+100P-100Q}=2^0=1$. DebRC answered Jan 17, 2023 DebRC comment Share Follow See all 2 Comments See all 2 2 Comments reply samarpita commented Jan 20, 2023 reply Follow Share lg PQR = lg P + lg Q + lg R => lg PQR = 100Q – 100R + 100R -100P + 100P – 100Q => lg PQR = 0 => lg PQR = lg 1 => PQR = 1 3 votes 3 votes DebRC commented Jan 20, 2023 reply Follow Share @samarpita Nice approach. 1 votes 1 votes Please log in or register to add a comment.