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In the echelon form of the augmented matrix $[A \mid b]:$ 

  1. A single row of the form $(000 \ldots 0 \mid 0)$ is enough to conclude that the system will have infinitely many solutions.
  2. A single row of the form (00 $\cdots 0 \mid 1)$ is enough to conclude that the system will have no solution.

 

  1. Only I is true.
  2. Only Il is true.
  3. Both I and II are true.
  4. Neither I, nor II are true.
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A row like $(000 \ldots 0 \mid 0)$ can indicate free variable (and column), but not necessarily infinite solution. We might still find a row of the form: $(00 \cdots 0 0 \mid c).$
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2 votes

Cross Example for Statement 1 to prove it False:

This is a Augmented Matrix with 3 variables and 5 equations.

$$\begin{bmatrix} a & b & c & d \\ 0 & e & f & g \\ 0 & 0 & h & i \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{bmatrix}$$
where, all alphabets are non-zero numbers.

We can see that last 2 rows are all zero, but still this equation will have a unique solution
because all the variables are pivot and there are 0 free variables.

For the solution to be infinite, there has to be a free variable.

Statement 2 is True because that is the condition for the No Solution.

For example,
0x = 3
It's a fact that No solution will exist for this.

Answer:

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