Question

. What will be the value returned by the following function, when it is called with 11?

recur (int num){

if ((num / 2)! = 0 ) return (recur (num/2) *10+num%2);

else return 1;

}

(a) Function does not return any value, because it goes into an infinite loop (b) 11 (c) 1011 (d) None of these

Answer 1

This is basically a program to get binary representation of a number. Given N, returns the binary for N

Comments

For n = 2, condition is true, since it is a divide not modulus sign in the condition.

Please check.

2/2 = 1

So 1!= 0 is true

Answer 2

a is the correct option. because function goes infinite loops, so it does  not return any value.

Answer 3

Function does not return any value because it goes into an infinite loop