C programming \ predict the ouptput

Question

void main()
{
    int i=10, j=2;
    int *ip= &i, *jp = &j;
    int k = *ip/*jp;
    printf(“%d”,k);
}

Comments

Ans 5

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no i executed the code. Its gives an error. It assumes that Fifth line has comment.  /*

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ok yes ,we have to write it with bracket

int k = (*ip)/(*jp);

Answer 1

IN LINE 5  the compiler treats the operator
sequence / and * as /* which happens to be the starting of
comment

SO IT GENERATES SYNTAX ERROR:UNEXPECTED END OF FILE.

HERE IS THE REFERENCE(MAXIMAL MUNCH)

https://en.wikipedia.org/wiki/Maximal_munch

Comments

but if I place space between / and * ; execution is fine and 5 is printed. Correct me if I'm wrong.

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yes u r rt.a white space or using like this [x=y/(*z);] will print 5

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@lord krishna bcz if u seprate / * by a space then they treat as *jp . but if u r not doing seprate by using space then  they treat like as starting of comment

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So operator precedence rule fail here.beacuse unary operator * has more precendece then '/' operator.

Is this the only case where the rule fail?