4 votes 4 votes The cubic polynomial $y(x)$ which takes the following values: $y(0)=1, y(1)=0, y(2)=1$ and $y(3)=10$ is $x^3 +2x^2 +1$ $x^3 +3x^2 -1$ $x^3 +1$ $x^3 -2x^2 +1$ Numerical Methods isro2009 polynomials + – go_editor asked Jun 15, 2016 • edited Jan 24 by makhdoom ghaya go_editor 1.9k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 5 votes 5 votes Ans D) y(x)=x3-2x2+1 Now, putting x=0 we get y(x)=0-0+1=1 Similarly x=1 we get y(x)=0 x=2 then y=1 x=3 then y=10 srestha answered Jun 15, 2016 • selected Jun 24, 2016 by Anu srestha comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Answer is D Option D: x^3 - 2 x^2 +1 =x^2(x-2) +1 Now put x values you'll get answer as option D (PS: key point here is solve these type of questions using this technique, take common power of x and then solve) Devwritt answered Mar 10, 2019 Devwritt comment Share Follow See all 0 reply Please log in or register to add a comment.