1 votes 1 votes The number of integer (positive, negative or zero) solutions of xy – 6(x+y) = 0 with {x \le} y is (A) 5; (B) 10; (C) 12; (D) 9. Quantitative Aptitude quantitative-aptitude + – . asked Jul 19, 2016 • edited Jul 19, 2016 by . . 1.6k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 0 votes 0 votes XY-6(X+Y)=0 XY-6(X+Y)+36=36 XY-6X-6Y+36=36 X(Y-6)-6(X-6)=36 (X-6)(Y-6)=36 the factors can be (0,0) (-3,2) (2,-3) (-6,3) (3,-6) (4,-12) (-12,4) (-30,5) (5,-30) is this correct? . answered Jul 19, 2016 . comment Share Follow See 1 comment See all 1 1 comment reply Riyank arora commented Apr 20, 2017 reply Follow Share No, your answer is incorrect Since if you'll reduce the equation further by dividing through xy and taking common you'll get 1/x + 1/y = 1/6 So x and y cannot form ordered pair of (0,0) Also you didn't include the ordered pair (6,6) as per the given condition x is less than or equal to y, so (6,6) will be included while (0,0) won't 0 votes 0 votes Please log in or register to add a comment.
