1 votes 1 votes The number of 1’s present in the binary representation of $10 \times 256 + 5 \times 16 + 5$ is $5$ $6$ $7$ $8$ Others ugcnetcse-june2011-paper2 + – makhdoom ghaya asked Aug 22, 2016 makhdoom ghaya 1.6k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes 10×256+5×16+5 =10×162+5×161+5×160 =(A55)16 =(1010 0101 0101)2 So 6 1's are there so option B is the Ans. Rajesh Pradhan answered Aug 22, 2016 • edited Aug 22, 2016 by Rajesh Pradhan Rajesh Pradhan comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 10 * 256 + 5 * 16+ 5 = 2645 convert 2645 into boolean by dividing with 2. Answer: (B) rishu_darkshadow answered Sep 13, 2017 rishu_darkshadow comment Share Follow See all 0 reply Please log in or register to add a comment.