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Leaky Bucket

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In a leaky bucket system if the output rate is 5 KB/sec and input burst of 50 KB/sec for 10 sec and 10 KB/sec for 50 sec then bucket size in KB is ...............
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Input burst = 50KB/sec for 10 sec  and 10KB/sec for 50sec.

Output rate = 5KB/sec

Total time = 60sec ,Total Length = 500KB + 500KB = 1000KB.

Now output rate = 5KB ------ 1 sec 

                                ?    ------   60sec

In 60sec we can transmit 300KB.

We should have a Bucket of size 1000KB - 300KB = 700KB

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