0 votes 0 votes consider a system where each file is associated with a 16 bit number.for each file ,each user should have the read and write capability.how much memory is needed to store each user's access data? A) 16KB B) 32KB C) 64KB D) 128KB Monika Sharma 1 asked Dec 10, 2016 Monika Sharma 1 632 views answer comment Share Follow See 1 comment See all 1 1 comment reply focus _GATE commented Dec 10, 2016 reply Follow Share i think this question is incomplete.?? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes D. no of file = 2^16. total bits required for access information = 2 one for read and one for write. per user memory required= 2^16*2 = 128KB Tendua answered Dec 10, 2016 Tendua comment Share Follow See all 6 Comments See all 6 6 Comments reply Aghori commented Dec 10, 2016 i edited by Aghori Dec 10, 2016 reply Follow Share It is 1 bit I think. Thanks. 0 votes 0 votes Monika Sharma 1 commented Dec 10, 2016 reply Follow Share can u please check the below post https://gateoverflow.in/51378/os 0 votes 0 votes Monika Sharma 1 commented Dec 10, 2016 reply Follow Share @tendua,, even mine answer is also 128KB. can u please check below post https://gateoverflow.in/51378/os 0 votes 0 votes Tendua commented Dec 10, 2016 reply Follow Share 1 bit for read and 1 bit for write so 2 bit. or there r 4 cases. read access and write acess , no read but write .... 0 votes 0 votes Tendua commented Dec 10, 2016 reply Follow Share I feel it wrong. The way they have done it is.calculated memory first. But memory = no of files * 16 bit.( if 16 bit are not used for addressing + no relation between file and memory given) number of file is not given which means it is given to say that from 16 bit we can address every possible file. 0 votes 0 votes Monika Sharma 1 commented Dec 11, 2016 reply Follow Share yes...@tendua 0 votes 0 votes Please log in or register to add a comment.