0 votes 0 votes Qus 1 Qus 2 Vasu_gate2017 asked Dec 11, 2016 Vasu_gate2017 answer comment Share Follow See 1 comment See all 1 1 comment reply santhoshdevulapally commented Dec 12, 2016 reply Follow Share Q1)applying limit in the form of 0/0 so apply L-hospitals rule for both numerator and denominator independently. we get $lim_{x->1} -e^{-x}/1$ then apply limit =-1/e Q2) same applying limit 0/0 after apply L-hospitals rule $lim_{x->0} (\frac{p}{1+px})/3.e^{3x}$ =p/3 1 votes 1 votes Please log in or register to add a comment.