3 votes 3 votes Compute approximate optimal window size when packet size is 53 bytes, the RTT is 60 micro seconds and bottleneck bandwidth is 155 Mbps? Computer Networks computer-networks + – focus _GATE asked Dec 16, 2016 focus _GATE 3.1k views answer comment Share Follow See all 9 Comments See all 9 9 Comments reply Digvijaysingh Gautam commented Dec 17, 2016 reply Follow Share window size = $\frac{B*RTT}{packet size}$ = $\frac{155*10^{6}*60*10^{-6}}{53*8}$ = 21.93 that means answer should be 21 3 votes 3 votes focus _GATE commented Dec 17, 2016 reply Follow Share why we not take 22 ?? 0 votes 0 votes Digvijaysingh Gautam commented Dec 17, 2016 reply Follow Share becoz we can accomodate only 21.93, that means 22th packet is partial. If we consider it whole then it will overflow the window size. Consider this using this example, Their is a vessel of capacity 21.93lt now u cant put 22lt in it. But u can put 21lt 3 votes 3 votes focus _GATE commented Dec 17, 2016 reply Follow Share k thanks 0 votes 0 votes bibhas kumar commented Dec 19, 2016 reply Follow Share why not 22 ? we know window size =1+2a =22.93 =22 .please clarify me 1 votes 1 votes focus _GATE commented Dec 21, 2016 reply Follow Share read digvijay comment :) 0 votes 0 votes stanchion commented Oct 26, 2017 reply Follow Share Yes, bibhas kumar is right. AS per Sliding window is concern, window size is calc. by: Window size= 1+2a = floor(1+ 21.93) = floor(22.93) = 22 Correct me if i am wrong. 0 votes 0 votes Groot commented Jan 2, 2018 reply Follow Share refer https://gateoverflow.in/1820/gate2006-44 0 votes 0 votes Venkat Sai commented Jan 21, 2018 reply Follow Share @stanchion its not mentioned that its sliding window so dont assume what digvijay singh said is right 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes BD product= RTT*Bandwidth =155∗106∗60∗10−6=155*60 packet size 53*8 so optimal window size=(155*60)/(53*8)=21.93 =22 Aboveallplayer answered Dec 26, 2016 Aboveallplayer comment Share Follow See all 2 Comments See all 2 2 Comments reply Ravit Anand commented Oct 9, 2017 reply Follow Share Why you are taking 22? 0 votes 0 votes mohitbawankar commented Dec 11, 2017 reply Follow Share Window size= floor ( BW*RTT / packet size) =floor (155∗10^6∗60∗10^−6/53*8) = floor(21.93)=21 0 votes 0 votes Please log in or register to add a comment.