0 votes 0 votes How large a file can be addressed by a double indirect block alone in a 64 bit system?minimum block entry size 8 byte and block size 8KB Operating System operating-system unix inode + – Aboveallplayer asked Dec 31, 2016 Aboveallplayer 330 views answer comment Share Follow See 1 comment See all 1 1 comment reply focus _GATE commented Dec 31, 2016 reply Follow Share 8GB ?? 1 votes 1 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes number of pointers in one disk block = 8kb/8k =1k since it is a double indirect pointer.. therefore number of pointers coming out= 1k * 1k now total size= (1k * 1k)8 kb =8gb Abhinandan Sharma answered Dec 31, 2016 • selected Jan 2, 2017 by Aboveallplayer Abhinandan Sharma comment Share Follow See all 0 reply Please log in or register to add a comment.
