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Recent activity by Karishma Datt
1
answer
1
TIFR CS & SS 2018 SS part Question 12
Suppose that Amitabh Bachchan has ten coins in his pocket. 3 coins have tails on both sides. 4 coins have heads on both sides. 3 coins have heads on one side and tails on the other and both the outcomes are equally likely when that coin is ... coins, flips it and finds that the outcome is tails. What is the probability that the other side of this coin is heads?
Suppose that Amitabh Bachchan has ten coins in his pocket. 3 coins have tails on both sides. 4 coins have heads on both sides. 3 coins have heads on one side and tails on...
704
views
commented
Dec 5, 2022
Probability
probability
conditional-probability
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1
answer
2
How many BoardCast Domain and Collision Domain?
1.1k
views
comment edited
Dec 2, 2022
Computer Networks
computer-networks
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0
answers
3
Thomas write rule
Need some help , In this question W3(B) , W2(B) is allowed in TWR bit confuse between option b and d . Plz help me which option is correct between b and d with proper justification.
Need some help , In this question W3(B) , W2(B) is allowed in TWR bit confuse between option b and d . Plz help me which option is correct between b and d with proper jus...
435
views
commented
Jul 24, 2022
Databases
databases
thomas-write-rule
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0
answers
4
Time Stamp Protocol
Need help in time stamp ordering .
Need help in time stamp ordering .
258
views
asked
Jul 24, 2022
Databases
databases
time-stamp-ordering
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0
answers
5
Theory of Computation, Regular language
Need help , to identify the regular languages
Need help , to identify the regular languages
334
views
commented
Jul 17, 2022
Theory of Computation
theory-of-computation
test-series
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1
answer
6
Regular Expression
Identify whether the language is regular or not and plz justify the ans.
Identify whether the language is regular or not and plz justify the ans.
374
views
commented
Jul 17, 2022
Theory of Computation
theory-of-computation
regular-language
test-series
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2
answers
7
why (a+b+c)*!= (a*+b*+c*) and why (a+b+c)* = (a*+b*+c*)*
From (a+b+c)* we can generate either a or b or c and kleene closure of that alphabet i.e a* or b* or c* which is same as (a*+b*+c*) .
From (a+b+c)* we can generate either a or b or c and kleene closure of that alphabet i.e a* or b* or c* which is same as (a*+b*+c*) .
612
views
commented
Jun 25, 2022
Theory of Computation
theory-of-computation
regular-expression
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0
answers
8
Proof (a* b*)* = (a + b)*
(a*b*)* = (a + b)* I always used this while solving questions. It seems correct also because when ever I pick a random string over {a, b} then I found that it can be generated from (a*b*)*. But I don't have any formal proof for this. Someone, please proof this.
(a*b*)* = (a + b)*I always used this while solving questions. It seems correct also because when ever I pick a random string over {a, b} then I found that it can be gener...
12.2k
views
commented
Jun 24, 2022
Theory of Computation
regular-expression
theory-of-computation
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