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Determine the cardinality of the following set

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Smallest value of $x$ $= \lceil \frac{1}{8} \rceil = 1$

Largest value of $x$ $ = \lfloor \frac{17}{2} \rfloor = 8$

Thus 8 integer values- $\{1, 2, 3, 4, 5, 6, 7, 8\}$.
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x value is between 1/8 to 17/2 ie. 0.125<x<8.5.

and x is an integer so between 0.125 to 8.5 there are 8 integers {1,2,3,4,5,6,7,8} so x can be any of these. so cardinality of the set is 8
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