The answer should be D.
CLA – clears the accumulator
ADD 217, Adds contents of location 217 with the Accumulator and stores in accumulator. Hence now contents of AC = 1234H
INC – increments acc (accumulator), hence value at 217 is 1234H + 1H = 1235H
STA 217 – store acc to location 217.
LDA 218 – load contents at 218 to acc. Hence acc = 9CE2H
CMA – complements the value at acc. Thus now acc = 631DH
AND 217 – performs bitwise AND of acc with contents of memory location 217 and stores the result in acc.
Thus acc = 1235H & 631DH which equates to 0215H
Hence the correct option is D.
