Prog \ What is the output of this program?

Question

#include<stdio.h>
int main()
{
    int a[10][20][30] = {0};
    int *b = a;
    int *c = a+1;
    printf("%ld", c-b);
    return 0;
}

Answer 1

Here a is 3D array .Suppose base address of a is 1000.

 int *b = a;

b is pointing the address of a  So b will contain 1000.

 int *c = a+1;

Here c containing the address of a+1 i.e. a plus it will skip 1 2D array (20*30*4) so 2400+100 i.e.2500 .

Here Subtracting two Pointers.

Final Result  = (ptr2 - ptr1) / Size of Data Type

So finally c-b =2500-1000=2400/4

600 will be printed.

Comments

I M NOT GETTING THIS TERM HERE:

Here c containing the address of a+1 i.e. a plus it will skip 1 2D array (20*30) so 1600 

CAN U PLZ MAKE ME UNDERSTAND