1 votes 1 votes (wx+yz)+(w'+x')(y'+z') ans is 1 Pravin Paikrao asked Jun 20, 2016 Pravin Paikrao 835 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes (wx+yz)+(wx)'.(yz)' =(wx+yz+(wx)')(wx+yz+(yz)') =(yz+1)(wx+1) =1*1=1 Pravin Paikrao answered Jun 20, 2016 • selected Jun 20, 2016 by LeenSharma Pravin Paikrao comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes WX + (WX)' + YZ + ( YZ )' 1 + 1 1 rameshbabu answered Jun 20, 2016 rameshbabu comment Share Follow See all 2 Comments See all 2 2 Comments reply Pravin Paikrao commented Jun 20, 2016 reply Follow Share thanks u gave me idea 0 votes 0 votes rameshbabu commented Jun 20, 2016 reply Follow Share go through laws of boolean algebra here in above question we used, A + A' = 1 and de morgan's law ( AB )' = A' + B' 0 votes 0 votes Please log in or register to add a comment.
