the logical address is divided as
48MB process === 3 * 2^24
Number of pages in process is === 3 * 2^10
on third level each page table provide 2^12 enteries so
3 * 2^10 entries is fit in one page
and in 2 nd level we need 1 page table
and on 1st level we need one page so ans is
3 pages + size of process
3*16KB +48 MB