Register

ISRO2013-ECE Digital Logic

• edited by
1,645 views

1 Answer

Best answer
1 votes
1 votes

Now the clock period as can be seen has doubled, which implies frequency is divided by 2. So answer is A)2

• selected by
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

2 votes
2 votes
2 answers
1
sh!va asked Feb 27, 2017
2,702 views
ISRO2013-ECE Digital Logic
What is the frequency and duty cycle of output $\text{Y},$ when CLK frequency is $\text{1MHz} \;@\; 50\%$ duty cyle? $500 \;\text{KHz} \;@\; 50\%$ duty cycle $500 \;\text{KHz} \;@\; 25\% $duty cycle $250 \;\text{KHz} \;@\; 50\%$ duty cycle $250 \;\text{KHz} \;@\; 25\%$ duty cycle
What is the frequency and duty cycle of output $\text{Y},$ when CLK frequency is $\text{1MHz} \;@\; 50\%$ duty cyle?$500 \;\text{KHz} \;@\; 50\%$ duty cycle$500 \;\text{K...
User Avatar
4 votes
4 votes
1 answer
2
sh!va asked Feb 27, 2017
4,048 views
ISRO2013-ECE Digital Logic
If a counter having $10$ flip flops is initially at $0,$ what count will it hold after $2060$ pulses? $000\; 000\; 1100$ $000 \;001\; 1100$ $000 \;001\; 1000$ $000 \;000\; 1110$
If a counter having $10$ flip flops is initially at $0,$ what count will it hold after $2060$ pulses?$000\; 000\; 1100$$000 \;001\; 1100$$000 \;001\; 1000$$000 \;000\; 11...
User Avatar
1 votes
1 votes
2 answers
3
sh!va asked Feb 27, 2017
1,110 views
ISRO2013-ECE: Digital Logic
Which of the following is the Boolean function for majority voting, assuming $\text{A, B, C}$ are inputs and $\text{Y}$ is output? $\text{Y = AB + AC + BC}$ $\text{Y = A + B + C}$ $\text{Y = ABC}$ $\text{Y= AB + BC}$
Which of the following is the Boolean function for majority voting, assuming $\text{A, B, C}$ are inputs and $\text{Y}$ is output?$\text{Y = AB + AC + BC}$$\text{Y = A + ...
User Avatar
2 votes
2 votes
2 answers
4
sh!va asked Feb 27, 2017
9,106 views
ISRO2013-ECE 2s compliment number
The two numbers represented in signed $\text{2s}$ complement form are $\text{P}= 11101101$ and $\text{Q}= 11100110.$ If $\text{Q}$ is subtracted from $\text{P},$ the value obtained in signed $\text{2s}$ complement form is: $1000001111$ $00000111$ $11111001$ $111111001$
The two numbers represented in signed $\text{2s}$ complement form are $\text{P}= 11101101$ and $\text{Q}= 11100110.$ If $\text{Q}$ is subtracted from $\text{P},$ the valu...
User Avatar
Link Copied!