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5 votes
5 votes

An organization is granted the block $130.34.12.64/26.$ It needs to have $4$ subnets. Which of the following is not an address of this organization?

  1. $130.34.12.124$
  2. $130.34.12.89$
  3. $130.34.12.70$
  4. $130.34.12.132$
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3 Answers

Best answer
5 votes
5 votes
The 4 subnets :

130.34.12.64-130.34.12.79

130.34.12.80-130.34.12.95

130.34.12.96-132.34.12.111

130.34.12.112-130.34.12.127

So ans is d
6 votes
6 votes

The block given to the Organization here is,

130.34.12.64/26 
so,

255.255.255 .1100 0000 (MASK)
130.34.12    .0100 0000 (IP Start Address)
-------------------------------------------------------------

Complementing The Mask ,We will be able to get the range of the IP's available to the Organization.

00000000 00000000 00000000 00111111=64

Dividing it into four subnets will give 

130.34.12.64
130.34.12.65
130.34.12.66
............
130.34.12.127

It is clearly visible that option : D) is the answer.

 

2 votes
2 votes
130. 34. 12. 01 000000
NID NID NID NID HID

26 bit NID. HID is 6 bits.

So hosts possible = 64.

Divide into four subnets => 16 per subnet.

So, last octets: .64 to .79, .80 to .95, .96 to .111, .112 to .127

which makes Option D out of range.

Answer:

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