logarithmic function<polynomial functions<exponential functions(comparison)
f1(n)=n0.999999logn
f2(n)=10000000n
f3(n)=1.000001n
f4(n)=n2
1-we can clearly see that f3(n) is exponential function and all other are polynomial function so f3(n) is greatest between all.
2-f2(n) is less than f4(n) for sure for larger value of n .
3-now come to f1(n) and f2(n) ,cancel the common terms from each now f1(n)=logn and f2(n)=n.000001 we can clearly see that f1(n) is logarithmic and f2(n) is polynomial so f2(n)>f1(n) (for large values of n)
from the above discussion we can say that f1(n)<f2(n)<f4(n)<f3(n).