question is:-

PRE ORDER :- 1,2,3,4,5,6,7,8,9,10,11,12

POST ORDER :- 3,5,4,2,7,8,6,10,11,12,9,1.

Draw the tree, but in the question they didn't specify it is binary or ternary or something else.

i hope they forget it by mistake.

Just assume is it can be a Binary tree?

Pre oder :- Data, Left, Right ( 1st node should be root )

( first node should be root, next to the root node is should be left node of root, if in post-order it is not in place of 2nd last node )

Post order :- Left, Right, Data

( last node should be root, before the last node it should be right node of root, if in pre-order it is not in place of 2nd node )

Now i conclude that, 9 is right of 1 and 2 is left of 1

PRE ORDER :- 1,${\color{Red} {2,3,4,5,6,7,8}} ,{\color{Green}{9,10,11,12}}$

POST ORDER :- ${\color{Red} {3,5,4,2,7,8,6}},{\color{Green} {10,11,12,9}}$,1.

clearly observe that, the right of root contains 9,10,11,12 ===> leave 9 due to it is fixed at immediate right of root.

so remaining elements are 10,11,12.

what is pre-order of those elements ?

10,11,12

what is the post order of those elements?

10,11,12

Is it possible in Binary Tree? (check all 5 trees which can formed by 3 nodes)

NO

Just assume it can be a Ternary Tree

PRE ORDER :- 1,2,3,4,5,6,7,8,9,10,11,12

POST ORDER :- 3,5,4,2,7,8,6,10,11,12,9,1.

2 is left most and 9 is right most, the childs of 9 is 10,11,12 from left to right.

For clear image https://drive.google.com/open?id=1Q1NO4GFEIOhoDPGXeWactpFsk0OByCY7