During delete, the root element is removed, replaced with the last element and heap property is corrected by pushing the root downwards. So, for first delete,
$25 \ 14 \ 16 \ 13 \ 10 \ 8 \ 12 \rightarrow 12 \ 14 \ 16 \ 13 \ 10 \ 8 \rightarrow 16 \ 14 \ 12 \ 13 \ 10 \ 8$ (the element not satisfying max-heap property is exchanged with the largest of its children) (heap property satisfied)
Second delete:
$16 \ 14 \ 12 \ 13 \ 10 \ 8 \rightarrow 8 \ 14 \ 12 \ 13 \ 10 \rightarrow 14 \ 8 \ 12 \ 13 \ 10 \rightarrow 14 \ 13 \ 12 \ 8 \ 10$ (heap property satisfied)
Correct Answer: $D$