GATE CSE 2025 | Set 2 | Question: 53

Question

Consider the following C program:

#include <stdio.h>

int g(int n) {
    return (n+10);
}

int f(int n) {
    return g(n*2);
}

int main() {
    int sum, n;
    sum=0;
    for (n=1; n<3; n++)
         sum += g(f(n));
    printf ("%d", sum);
    return 0;
}

The output of the given C program is ___________. (Answer in integer)

Comments

 The Answer is 46.

See here.

Answer 1

Let us first expand the expression given in the main function;

sum+=g(f(n)) can be written as sum=sum+g(f(n))

now, coming to the for loops, it is run two times.

when $n=1,1<3:T$,it is called as $0+g(f(1))$.

when $f(1)$ is called it return $g(2)$ which is go to function g(n) where it is executed $10+2$ and return $12$ to main fuction.again

sum=0+g(12), now we call one more time $g(n)$ this time it return $10+12=22$.Therefore final value of the sum after the first iteration is $22.$

now increment $n++$ gives $n=2,2<3:T$, loop will run one more time as $sum=22+g(f(2))$

when $f(2)$ is called it return g(4) which go to function $g(4)$ and it return as $10+4=14$ to main fuciton.

so $sum=22+g(14)$, now $g(14)$ will return again $10+14=24$. so the final value of the sum is $22+24=46$

so the output of the given program is $46.$

Comments

are yrr 1 se loop chalu tha paper me andha hogya tha -2 hogya rip

---

i did not get g(12)  giving 10

and g(14) giving 10

explain

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maine 1 se loop suru hai ye toh dekha but condition is n<3, and what my eye saw n<=3,   damn -2

Answer 2

int g(int n) {
    return (n+10);
}

int f(int n) {
    return g(n*2);
}

for (n = 1; n < 3; n++) 
    sum += g(f(n));

When n = 1:

• f(1) → g(1*2) → g(2) → 2 + 10 = 12   // in this step, someone make mistake

• g(f(1)) → g(12) → 12 + 10 = 22

When n = 2:

• f(2) → g(2*2) → g(4) → 4 + 10 = 14

• g(f(2)) → g(14) → 14 + 10 = 24

 

sum = 22 + 24 = 46
ans is 46

Answer 3

When n = 1:
         f(1) = g(1 * 2) = g(2) = 2 + 10 = 12

         g(f(1)) = g(12) = 12 + 10 = 22

         sum = sum + 22 => sum = 0 + 22 = 22

         When n = 2:
         f(2) = g(2 * 2) = g(4) = 4 + 10 = 14

         g(f(2)) = g(14) = 14 + 10 = 24

         sum = sum + 24 => sum = 22 + 24 = 46

Answer 4

TRACE THE CODE....
HERE IS ROUGH WORK.....
Final Answer is 46....