0 0 votes What will be the "First" and "Follow" of $\mathrm{E}$ and $\mathrm{F}$ for the following grammar?$\mathrm{E}->\mathrm{TE}{ }^{\prime}$$\mathrm{E}^{\prime}->+\mathrm{TE}{ }^{\prime} / \varepsilon$$\mathrm{T}->\mathrm{FT}^{\prime}$$\mathrm{T}^{\prime}->^{*}\text{FT}{ }^{\prime} / \varepsilon$$\mathrm{F}->\mathrm{id} /(\mathrm{E})$$\operatorname{First}(\mathrm{E})=\{\mathrm{id},(, \varepsilon\}, \operatorname{Follow}(\mathrm{E})=\{\varepsilon,)\}, \operatorname{First}(\mathrm{F})=\{\mathrm{id,}), \$\}, \operatorname{Follow}(\mathrm{F})=\{*, \$,( \}$$\operatorname{First}(\text{E})=\text{i d},( \}, \operatorname{Follow}(\text{E})=\{\$,)\}, \operatorname{First}(\text{F})=\text{i d},( \}, \operatorname{Follow}(\text{F})=\{*, \$,),+\}$$\operatorname{First}(\mathrm{E})=\{\mathrm{id,}), \varepsilon\}, \operatorname{Follow}(\mathrm{E})=\{\varepsilon,)\}, \operatorname{First}(\mathrm{F})=\{\mathrm{id},)\}, \operatorname{Follow}(\mathrm{F})=\{*, \mathrm{\$},(,+\}$$\operatorname{First}(\mathrm{E})=\{\mathrm{id,})\}, \operatorname{Follow}(\mathrm{E})=\{\$,)\}, \operatorname{First}(\mathrm{F})=\{\mathrm{id,}(, \$\}, \operatorname{Follow}(\mathrm{F})=\{*, \mathrm{\$},),+\}$ Others cil-2017 + – Shubham Sharma 2 29 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.