Register

SSTF Disk Scheduling

3,200 views
1 1 vote

My answer is 202
given 232

6 Answers

Best answer
2 2 votes
60 - 53 = 7
53 - 39 = 14
39 - 37 = 2
37 - 28 = 9
28 - 14 = 14
98 - 14 = 84
122 - 98 = 24
170 - 122 = 48
Total head movements = (7 + 14 + 2 + 9 + 14 + 84 + 24 + 48) = 202
• selected by
Voting & Accepting an answer helps improve the community
← Previous · graphs-eulerianNext → · how to solve thiz ty...
← Previous in category · OS DOubtNext in category → · SemaPhore
Position:
Show:

Related questions

3 3 votes
1 1 answer
153
153 views
GO Classes asked Aug 26
153 views
GO Classes DPP | GATE CS | Operating System | SSTF Disk Scheduling
A disk contains tracks numbered from $0$ through $199$.The disk head is currently at track $184$.The pending requests, in arrival-list order, are $184, 187, 176, 182, 199...
1 1 vote
4 4 answers
1.3k
1.3k views
Rahul_Rathod_ asked Dec 21, 2018
1,250 views
MadeEasy Test Series: Operating System - Disk Scheduling
1 1 vote
2 2 answers
2.5k
2.5k views
jatin khachane 1 asked Dec 13, 2018
2,512 views
MadeEasy Subject Test 2019: Operating System - Disk Scheduling
I got LOOK == 260CSCAN == 383
1 1 vote
0 0 answers
2.3k
2.3k views
jatin khachane 1 asked Dec 11, 2018
2,297 views
Self Doubt Disk Scheduling
Suppose a disk has 100 cylinders, numbered from 0 to 99. At some time the disk arm is at cylinder 20, and there is a queue of disk access requests for cylinders 10, 22, 6...