0 votes 0 votes The problem: Given: $B=$ 64 kbps satellite channel $L=$ 512 B data frames Round Trip Time (RTT) = 64 ms What is the maximum throughput for window size of 1? Computer Networks stop-and-wait computer-networks sliding-window + – GateAspirant999 asked Jan 18, 2017 edited Jan 18, 2017 by GateAspirant999 GateAspirant999 2.7k views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Mahima Manik commented Jan 24, 2017 reply Follow Share 11.11%? 0 votes 0 votes Anmol Verma commented Jan 25, 2017 reply Follow Share is ans 32kbps....??? 0 votes 0 votes anonymous commented Mar 30, 2017 reply Follow Share how did you get 11.11% ?? can u plz explain . 0 votes 0 votes Please log in or register to add a comment.
4 votes 4 votes Throughput=Efficiency * Bandwidth Efficiency= Transmission Time/(Transmission Time+ Round Trip Time) Tt=Length of Pkt/Bandwidth Tt=512*8/(64*10^3)=64 msec Therefore, Efficency=64/(64+64)=0.5 Thus, Throughput=0.5*64 kbps=32 kbps. Anirudh Pandey answered Feb 5, 2017 Anirudh Pandey comment Share Follow See all 0 reply Please log in or register to add a comment.