0 0 votes The maximum length of the cable (min) for transmitting data at a rate of 800 Mbps in IEEE 802.3 LAN with a frame size of 16,000 bits is ________ km. Assume the signal speed in the cable to be, 2,50,000 km Computer Networks + – iita 672 views answer comment Share Follow Print See all 3 Comments 3 3 Comments reply G.K.T commented Jan 31, 2017 reply Follow flag Confirm the speed ? Is it in km/sec ? 0 0 replyShare iita commented Jan 31, 2017 reply Follow flag they have not given anything on that but i took km/sec 0 0 replyShare G.K.T commented Jan 31, 2017 i edited by G.K.T Jan 31, 2017 reply Follow flag Transmission time equals twice the propagation time Tt = frame size / bandwidth Tp = length/velocity Let length be x 16000 / 800*106 = 2* x / 250000*103 X=2500 m Or 2.5 Km 0 0 replyShare Please log in or register to add a comment.
0 0 votes Getting 2.5 km when considering velocity as 250000km/sec. What is the answer given? nandini gupta answered Jan 31, 2017 nandini gupta comment Share Follow See 1 comment 1 1 comment reply iita commented Jan 31, 2017 reply Follow flag they have given 5 km..even I got 2.5 0 0 replyShare Please log in or register to add a comment.
