GATE CSE 2007 | Question: 19

Question

In Ethernet when Manchester encoding is used, the bit rate is:

• A. Half the baud rate

• B. Twice the baud rate

• C. Same as the baud rate

• D. None of the above

Comments

Is this topic present in the current syllabus?

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Refer -> https://stackoverflow.com/questions/25834577/why-in-manchester-encoding-the-bit-rate-is-half-of-the-baud-rate 

Just additional information -

You can think of Manchester encoding not only transmitting the actual data, but also the clock (meta data) due to its self clocking characteristic.

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bit --> 3 letters
baud --> 4 letters
baud > bit

Answer 1

Bit rate is half the baud rate in Manchester encoding as bits are transferred only during a positive transition of the clock.

http://stackoverflow.com/questions/25834577/why-in-manchester-encoding-the-bit-rate-is-half-of-the-baud-rate

Correct Answer: $A$

Answer 2

Basically there is a relation between bit rate and baud rate which is:

BaudRate = Bitrate * c * (1/r)

c = Case factor usually = 1 (if nothing mentioned in question)

r = data element per signal element

In manchester signal or differential manchester a data bit is encoded in two signal element so r = 1/2 because for half duration level is up and for half of bit duration its below so two signal element per data element

 

hence if we substitue the data of r in above we get Baud rate = 2* Bit rate

Answer 3

comment below if u have any doubt☺

Answer 4

ans b)

Comments

how?

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Baud rate = 2* Bit Rate.

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@Sandeep Suri

Note: Only in case of manchester encoding