pointer

Question

please tell how to solve it?

Comments

What is ur doubt here ?

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foo(ary); passes the base address to fn definition but how this base address is using in fn definition. i found difficulty to understand void foo(int p[4]) fn definition

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If you are coding them, why not add question as text?

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Hi Aakash1125,

Output will be - 10,1

You are correct that In C, array name represents address and when we pass an array.

Note: When we pass like that, we actually pass address and the parameter receiving function always accepts them as pointers.

The foo() function can also be written like this,

void foo(int *p)
{
    int i=10
    p = &i;
    printf("%d ", p[0]);
}

The pointer "p" will point to array initially, when we pass to function.

But when the statement,

p=&i;

executes, now "p" will point to the variable i.

so it would be like,

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thank you sir. I did not know (Note: When we pass like that, we actually pass address and the parameter receiving function always accepts them as pointers.)but now I feel at home with this concept... :)

Answer 1

hope it helps......

Comments

great,,,, thank you