program

Question

void main()

{

float a=55555;

printf("%.2E %.2e\n",a);

}

a)5.56E+004 8.12e+268

b)compilation error

c) runtime error

d)555.55E+002

Comments

Test ur C skill by kanetkar

not exactly this question...but this type of question

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Surely a misprint in question, but don't follow that book for GATE.

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ok tnk u sir

Answer 1

answer is A) 5.56E+004 8.12e+268

e    Scientific notation (mantissa/exponent), lowercase    
E    Scientific notation (mantissa/exponent), uppercase

Comments

plz be a bit clear...........%.2E means taking 2 digit after the point...but how 004?

and how got %.2e     =8.12e+268

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here 0.2 means after the point we have to consider 2 digit .

see 55555 = 5.5555 * E^4 = 5.56 * E^4  (round off upto 2 digit and 4 is +ve ) so 5.56E+004

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But how did you get the second value?

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I ran on Mac OS and got the below results:

test.c:13:18: warning: more '%' conversions than data arguments [-Wformat]
        printf("%.2E %.2e\n",a);
                     ~~~^
1 warning generated.
$ ./a.out

5.56E+04 0.00e+00

After i changed the line to:

printf("%.2E %.2e\n",a,a);

I got the result as:

./a.out

5.56E+04 5.56e+04