1 1 vote Consider a disk with these parameters: Number of surfaces $= 32$ Number of tracks / surface $= 64$ Number of sectors / track $= 1024$ Number of bytes stored in a bit serial manner in a sectors $= 256$ Let the capacity of the disk be $`L'$ MB, and the number of bits required to specify a particular sector in that disk be $`M'$ bits. The value of $L+5M$, therefore, is __________. Operating System tbb-mockgate-4 numerical-answers operating-system disk + – Bikram 680 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes capacity of Disk $=$ $surfaces * tracks/ surface * sectors per track * Bytes/ sector$ = $32 * 64 * 1024 * 256 Bytes$ = $2$^$29$ $Bytes$ = $512 MB$ Bits required to specify a sector $=$ $32 * 64 * 1024 $=$ 2$^$21 =$ $21 bits$ $L + 5M = 512 + 5 * 21 = 617$. akash.dinkar12 answered Aug 1, 2017 • edited Jan 29, 2018 by Andrijana3306 akash.dinkar12 comment Share Follow 0 reply Please log in or register to add a comment.