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Test by Bikram | Programming | Test 2 | Question: 21

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Char is of 1 Byte

range of singed char = {-2^n -1 to +2^n-1} = -128 to +127

char c =125

125+1= 126
125+2= 127
125+3=-128
125+4=-127
125+5=-126
125+6=-125
125+7=-124
125+8=-123
125+9=-122
125+10=-121
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8 votes
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(125= 01111101) + (10=00001010) = 10000111... showing overflow as addition of two positive numbers giving negative result.
Content of register = 10000111= -121 ( -2^7 + 7)
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