1 1 vote Is n^2 2^(3log base 2 n) = theta (n^5). Algorithms algorithms logarithmic-function normal + – Sidd_ 1.0k views answer comment Share Follow Print See 1 comment 1 1 comment reply Hemant Parihar commented Jun 4, 2017 reply Follow flag Yes . 2 ^ (log base 2 (n^3)) cab be written as n^3. As e ^( log base e (n) ) can be written as e. 0 0 replyShare Please log in or register to add a comment.
1 1 vote I am attaching the solution in the form of an image below where I have also proved the property of logarithms that is used in this question. asriv answered Jun 4, 2017 asriv comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes yes it is , it is simply simplification of log then you got n^5 Prateek Raghuvanshi answered Jun 6, 2017 Prateek Raghuvanshi comment Share Follow 0 reply Please log in or register to add a comment.
